A simple peasant bought a number of camels and is taking them to his farm. As he rides contentedly along he counts them - he counts 29. He was sure he had bought 30 camel, so in alarm he jumps off his camel and counts the camels again. To his delight there are 30. Half an hour later, he counts his camels and once more there are just 29. Confused, he climbs off his camel and counts again. Once more there are 30. Can you explain?
It could be delivered by mail, email, by hand, or even by pigeon.
It is sometimes short, sometimes lengthy, and with deep, profound, or simple feelings.
What is it?
In a recreational activity, you are given four different jars of 2 liters, 4 liters, 6 liters and 8 liters respectively with an unlimited water supply. Then you are asked to measure exactly 5 liters of water using them.
How will you do it?
We have two soap of equal weights and a 3/4 pound weight.
However, after using 1/4 of soap we place all three objects on balance as On one side of balance we place one soap (unused) and on another side, we placed used soap (i.e 3/4th of soap) and 3/4 pound weight.
What is the soap weight?
I have a clock in my house, on the wall.
On a summer's day I forgot to wind it and it stopped. Then I went to visit a friend who had a watch that was always right on time. After I stayed for a bit, I went home, made a simple alteration and set the clock just right.
Now how did I do this when I had no watch on me to tell how long it took me to come back from my friend's place?
Before I left, I wound the wall clock. Upon my return, the amount of change that I could see in the clock is how long it took to go to my friends place and come back, adding to that the time I spent there, which I know because the clock at my friend's place is accurate.
Subtracting the time of the visit from the time I was absent from my house, and dividing by 2, I obtained the time it took me to return home. I added this time to what my friend watch showed when I left, and set the sum on my wall clock.
You have 3 boxes. One of them contains a prize. You were allowed to pick just one of them.
You pick - and it's empty.
With 2 boxes left, you now have one box in your hand and another box in front of you. If given the chance to exchange your box with the box in front of you, would you do it? Why, and why not?
(The 'Google Riddles' are interview questions those who wish to get hired were asked).
In the beginning, with 3 boxes, things were simple. You had a chance of 1 in 3 to find the prize. NOW we know that one of the boxes is empty but you still made a guess of 1 in 3, now you have a new choice of 1 in 2. Your probability goes up and that is why you SHOULD CHANGE THE BOX.
Don't feel bad if you disagree, this riddle has been hotly debated.
Today is more windy than yesterday, will a return flight take the same time, less time, or the same amount of time to complete?
(The 'Google Riddles' are interview questions those who wish to get hired were asked).
Let's do a worked example. Lets say our plane has to travel 300 miles there and 300 miles back. It has a standard cruising speed of 600mph. In the case of no wind it will travel the 600 miles in 1 hour exactly. Simple enough. Let us say that the wind speed is 100mph so the plane will be wind assisted to 700mph and slowed to 500mph - Wind Assisted: 300 miles at 700mph takes 0.429 hours - Wind Slowed: 300 miles at 500mph takes 0.6 hours - Total Time: 1.029 hours
5 pirates are parting ways after finding a treasure of 100 pieces of gold. The pirates decide to split it based on a vote. Each pirate, from oldest to youngest, gets to propose a plan on how to split the gold.
If at least 50 percent of the other remaining pirates agree on the plan, that is how they will split the gold. If less than 50 percent of the pirates agree, the pirate who came up with the plan will be thrown overboard. Each pirate is smart, greedy, and wants to throw as many others overboard as possible without reducing the amount of gold they get.
What plan can the first (oldest) pirate propose to live and get as much gold as possible?
He can propose a plan that he gets 98 pieces of gold, the 3rd pirate gets 1 piece, and the 5th pirate gets 1 as well.
If there were just 2 pirates the younger pirate would definitely deny the plan so he could get all of the gold.
If there were 3 pirates the first pirate can offer the second pirate 1 piece of gold and take the rest himself because the second pirate wouldn't get anything if he has to propose a plan himself.
If there were 4 pirates the first pirate could take 99 for himself and offer 1 to the youngest pirate. They would both agree. If the youngest disagrees then he won't get any gold in the next plan.
So when there are 5 pirates it is in the interest of the 3rd and 5th pirate to accept 1 piece, because if they don't they won't get anything in the next plan.
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